cos^2(2x)+2sin^2(2x)=2

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Solution for cos^2(2x)+2sin^2(2x)=2 equation:


Simplifying
cos2(2x) + 2sin2(2x) = 2

Remove parenthesis around (2x)
cos2 * 2x + 2sin2(2x) = 2

Reorder the terms for easier multiplication:
2cos2 * x + 2sin2(2x) = 2

Multiply cos2 * x
2cos2x + 2sin2(2x) = 2

Remove parenthesis around (2x)
2cos2x + 2in2s * 2x = 2

Reorder the terms for easier multiplication:
2cos2x + 2 * 2in2s * x = 2

Multiply 2 * 2
2cos2x + 4in2s * x = 2

Multiply in2s * x
2cos2x + 4in2sx = 2

Solving
2cos2x + 4in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4in2sx' to each side of the equation.
2cos2x + 4in2sx + -4in2sx = 2 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
2cos2x + 0 = 2 + -4in2sx
2cos2x = 2 + -4in2sx

Divide each side by '2os2x'.
c = o-1s-2x-1 + -2in2o-1s-1

Simplifying
c = o-1s-2x-1 + -2in2o-1s-1

Reorder the terms:
c = -2in2o-1s-1 + o-1s-2x-1

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